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Tag: ISI

Week -12 | Combinatorics – 5

Posted on May 3, 2019 by bubuenaa

1.1 Principle of Inclusion and Exclusion This very important principle is a generalization of the Sum Rule to sets which need not be disjoint. Let’s say that we have 2 sets & . We look at the cardinality of the union of these 2 sets (We assume that students going through this module are familiar with… Continue reading

Week – 11 | Combinatorics – 3

Posted on April 28, 2019 by bubuenaa

1.1 Introduction to Generating Functions Consider a simple problem where we have to calculate the number of ways to choose 2 fruits from 5 distinct fruits. Let’s call them A,B,C,D,E. So we have 1 each of these 5 fruits and we need to choose 2 of them (ignoring the order). A simple way would be… Continue reading

Week -11 | Combinatorics – 2

Posted on April 27, 2019 by bubuenaa

1.1 Basic Cases and Circular Permutations In the last lecture we considered the basic concepts of permutations and combinations. Let’s consider a couple of examples further to ease the process of understanding these. Ex -1 Find the number of permutations of the word ‘TRIANGLE’. How many of these permutations start with ‘T’ and end with… Continue reading

Week – 10 | Inequalities – 4

Posted on January 12, 2019 by bubuenaa

Q-1) For the minimum value of  is __   Q-2) If  be the sides of a triangle, then the minimum value of  is a)     b)     c)     d)    Q-3) For positive reals ,  is always a)     b)     c)     d)    Q-4) For positive reals  in H.P which of the follwing… Continue reading

INMO – 1986 | A Problem on Polynomials

Posted on January 5, 2019 by bubuenaa

Q) If  is a polynomial with integer coefficients and  three distinct integers, then show that it is impossible to have  Solution: The solution revolves around an important property of integer coefficient Polynomials, For any 2 integers ,  is always divisible by . So from this we have  divides  which implies  divides ,  divides ,  divides . Once we have this, the remaining… Continue reading

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